Wednesday, July 28, 2010

Self Test #1 Complete


Sketch the symbals and label the leads for the two and three terminal devices

NPN.




MOSFET.
LED

ZENER DIODE
Q2. Fill in the blanks




Q3.

Q4: If V=IR and P=IV, what is P in terms of V and R
P=V2R

Vd = 0.7V. Diodes only require 0.7V to operate.







Q6, Vs=50V R1= 10Ohms Diode = 1W Max



Current Flow = (50-0.7)/10= 4.93 Amps



Q7, Pd=IdxVd Id=4.93, Vd=0.7 4.93 x 0.7 = 3.45W



Q8, Yes the diode will be destroyed. The maximum watt dissipation for the Diode is 1 watt and the total amount of watts this circuit will create on the diode will be too great for the diode to control.



Q9, Sketch a simple voltage regulator using discreet components



The zener diode acts as a 5V regulator, so any component placed on the same track as the zener diode will recieve 5V from the Zener Diode opposed from the 12v power supply.






Q10, Is the zener diode in the foward or reverse bias arrangement. Reverse

1 comment:

  1. Not bad, the NPN drawing is not correct.

    Remember a 10 ohm resistor is written as 10R.

    ReplyDelete