Experiment 1 complete

For experiment 1 I obtained 6 resistors of different values. I can tell they are of different value by the different colour bands on them. I then calculated the value of each resistor by using my colour code. The 1st resistor was brown, black, red, then gold. I then converted that information into a number which came out as 1,000 Ohms with 5% tolerance. (950 to 1050 Ohms) I then proceeded with the other 5 resistors and got values of

Brown, Black, Brown, Gold = 100 ohms with 5% tolerance (95-105 Ohms) Yellow, Violet, Brown, Gold = 470 Ohms with 5% tolerance(446.5-47.35 Ohms).

Brown, Black Orange, Gold = 10k with 5% tolerance (9500k-10500k).

Yellow, Violet, Orange, Gold = 47k with 5% tolerance (44.65k-47.35k)

Red, Red, Yellow, Gold = 220k with 5% tolerance. (209k-231k)

I then used my ohmeter and measured the value of each resistor and recorded its value.
My 100 Ohms resistor was 98.1 Ohms, 470 was 458 Ohms, 10k was 9.87k, 47k was 46.7k, 220k was exactly 220k.

I then took the two lowest value resistors and calculated the total resistance in series.
R1 + R2 = Rt 458 + 98.1 = 556.1 Ohms.
I then measured the total resistance with my Ohmeter and recorded 555 Ohms

Then I calculated the total resistance in parallel
Rt = R1 x R2/ R1 + R2 458 x 98.1 = 44929 458 + 98.1 = 556 44929/556 = 80.80 Ohms
I then measured the total resistance with my Ohmeter and recorded a total of 80.54 Ohms.

Alternatively, a formula of 1/458+1/98.1=0.012377086 1/0.012377086= 80.80 Ohms

With this information I have demonstrated, I can explain the principles of resistors paired in series and parallel.

Resistors in series are added together to get the resistance total whilst resistors in parallel are always less then any of the individual resistances. An easy way to calculate Rt with 2 equal resistors is to just half the amount of one resistor. For example two 100 ohm resistors connected in parallel will give a resistance total of 50 Ohms.